A box contains 6 red 8 green 10 blue 12 yellow and 15.
A box of marbles can be shared equally among 6 7 or 8 students.
N 6 integer i1 remainder 4 r 4 2.
N 8 integer i3 rem 4 r solution find lowest interger divisable by 6 7 8 and then add 4 first find a number nx that divide.
N 7 integer i2 rem 4 r 3.
If in the bag have 24 marbles student groups can have 6 8 10 respectively.
What s the least amount of marbles that can be in the bag.
A bag of marbles can be shared equally among 3 5 or 6 students with none left over.
A bag contains 100 marbles.
How many marbles do i have.
Well there s 8 possibilities 8 possibilities for my trial.
There is a bag of marbles on a table.
The marbles can be divided into equal shares among 6 7 or 8 children with 1 marble left over each time.
A bag of marbles can be shared equally among 3 4 5 students with none left over.
Answer 20 14y by 16y 4.
A set of marbles can be divided in equal shares among 2 3 4 5 or 6 children with no marbles left over.
When the marbles are shared among 3 people there are 2 marbles remaining.
What is the least number of marbles that.
And then you say well how many of those marbles meet my constraint that satisfy this event here.
Posts along the width and 8 posts along the length.
What is the least number of marbles that the box algebra distributive associative commutative properties solution.
Each pupil in group b had 4 marbles more than each pupil in group c.
If the pupils in group c received a total of 549 marbles how many marbles were shared out.
So the number of outcomes number of possible outcomes you could view it as the size of the sample space number of possible outcomes and it s as simple as saying look i have 8 marbles.
B how many marbles could be remaining if shared among 20 people.
When shared among 4 people there are 1 marbles remaining.
Bag of n number of marbles 1.
How many posts does tom need and what are the dimensions of the fence.
When i try to divide some marbles equally among 6 7 or 8 children each time i am left with the same number of marbles.
However i can equally divide them among 13 children.
There are 10 red marbles 8 blue marbles in a box and h yellow marbles are added and the probability of getting a blue marble from the box is 1 5.
A how many marbles would be remaining if shared among 2 people.